2x^2+12=4-x^2

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Solution for 2x^2+12=4-x^2 equation: 



2x^2+12=4-x^2

We move all terms to the left:

2x^2+12-(4-x^2)=0

We get rid of parentheses

2x^2+x^2-4+12=0

We add all the numbers together, and all the variables

3x^2+8=0

a = 3; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·3·8
Δ = -96
Delta is less than zero, so there is no solution for the equation

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